1. A program to evaluate the equation y=xn when n
is a non-negative integer. #include<stdio.h>
#include<conio.h>
void main()
{
int count, n;
float x,y;
printf(“Enter the values of x and n:”);
scanf(“%f%d”, &x,&n);
y=1.0;
count=1;
while(count<=n)
{
y=y*x; count++;
}
printf(“x=%f; n=%d; x to power n=%f”, x, n,y);
}
Output:
Enter the values of x and n: 2.5 4 X=2.500000;
n=4; x to power n= 39.062500
2. A program to print the multiplication table from 1*1 to 12*10.
#include<stdio.h>
#include<conio.h>
#define COLMAX 10
#define ROWMAX 12 void main()
{
int row, column, y; row=1;
printf(“MULTIPLICATION TABLE ”);
printf(“------------------------------------ ”);
do
{
column=1;
do
{
y=row*column; printf(“%d”, y); column=column
+1;
}
while(column<=COLMAX);
printf(“\n”);
row=row+1;
}
while(row<=ROWMAX);
printf(“---------------------------------------------- ”)
}
Output:
MULTIPLICATION TABLE
 |
1 2 3 4 5 6 7 8 9 10
2 4 6 8 10 12 14 16 18 20
3 6 9 12 15 18 21 24 27 30
4 8 12 16 20 24 28 32 36 40
5 10 15 20 25 30 35 40 45 50
6 12 18 24 30 36 42 48 54 60
7 14 21 28 35 42 49 56 63 70
8 16 24 32 40 48 56 64 72 80
9 18 27 36 45 54 63 72 81 90
10 20 30 40 50 60 70 80 90 100
11 22 33 44 55 66 77 88 99 110
12 24 36 48 60 72 84 96 108 120
3.
Program uses a for loop to print the powers of 2 table for the power 0 to 20, both positive
and negative.
#include<stdio.h>
#include<conio.h>
void main()
{
long int p; int n; double q;
printf(“------------------------------------------------------------- ”);
printf(“ 2 to
power n n 2 to power -n”);
printf(“------------------------------------------------------------- ”);
p=1;
for(n=0; n<21; ++n)
{
if(n==0)
P=1;
else
p=p*2;
}
}
Output:
q=1.0/(double)p;
printf(“10ld 10%d %20.12lf”, p,n,q);
}
printf(“---------------------------------------------- ”);
2 to power n n 2 to power -n
1
|
0
|
1.000000000000
|
2
|
1
|
0.500000000000
|
4
|
2
|
0.250000000000
|
8
|
3
|
0.125000000000
|
16
|
4
|
0.062500000000
|
32
|
5
|
0.031250000000
|
64
|
6
|
0.015625000000
|
128
|
7
|
0.007812500000
|
256
|
8
|
0.003906250000
|
512
|
9
|
0.001953125000
|
1024
|
10
|
0.000976562500
|
2048
|
11
|
0.000488281250
|
4096
|
12
|
0.000244140625
|
8192
|
13
|
0.000122070313
|
16384
|
14
|
0.000061035156
|
32768
|
15
|
0.000030517578
|
65536
|
16
|
0.000015258789
|
131072
|
17
|
0.000007629395
|
262144
|
18
|
0.000003814697
|
524288
|
19
|
0.000001907349
|
1048576
|
20
|
0.000000953674
|
4.
A class of n students take an annual
examination in m subjects. A program to read the marks
obtained by each student in various subjects
and to compute and print
the total marks
obtained by each of them.
#include<stdio.h>
#include<conio.h>
#define
FIRST 360
# define SECOND 240
void main()
{
int n, m, i, j, roll number, marks, total;
printf(“Enter number of students and subjects”); scanf(“%d%d”, &n,&m);
printf(“\n”);
for(i=1; i<=n; ++i)
{
printf(“Enter roll number:”);
scanf(“%d”, &roll_number);
total=0;
printf(“Enter marks of %d subjects for ROLL
NO”, m, roll number); for(j=1; j<=m; j++)
{
scanf(“%d”, &marks); total=total+marks;
}
printf(“TOTAL MARKS =%d”, total);
if(total>=FIRST)
printf(“(First division)”);
else if
(total>=SECOND) printf(“(Second division)”);
else printf(“(***FAIL***)”);
}
}
Output:
Enter number of students and subjects 3 6
Enter roll_number: 8701
Enter marks of 6 subjects for ROLL NO 8701 81
75 83 45 61 59
TOTAL MARKS =404 (First division) Enter
roll_number:8702
Enter marks of 6 subjects for ROLL NO 8702 51
49 55 47 65 41
TOTAL MARKS =308(Second division) Enter
roll_number: 8704
40 19 31 47 39 25
TOTAL MARKS=201(*** FAIL ***)
5. The program illustrates the use of the break
statement in a C program.
#include<stdio.h>
#include<conio.h>
void main()
{
int m;
float x, sum, average;
printf(“This program computes the average of a
set of computers”); printf(“Enter values one after another”);
printf(“Enter a NEGATIVE number at the end”);
sum=0;
for(m=1;m<=1000; ++m)
{
scanf(“%f”,&x); if(x<0)
break;
sum+=x;
}
average=sum/(float)(m-1); printf(“\n”);
printf(“Number of values =%d”,m-1);
printf(“sum=%f”, sum);
printf(“Average=%f”, average);
}
Output:
This program computes the average of a set of
numbers Enter values one after another
Enter a NEGATIVE number at the end 21 23 24 22
26 22 -1
Number of values =6 Sum= 138.000000
Average=23.000000
6.
A
program to evaluate the series 1/1-x=
1+x+x2 +x3 +.... +xn.
#include<stdio.h> #include<conio.h>
#define LOOP 100
#define ACCURACY 0.0001
void main()
{
int n;
float x, term, sum;
printf(“input value of x
:”); scanf(“%f”, &x);
sum=0;
for(term=1, n=1; n<=LOOP; ++n)
{
sum+=term; if(term<=ACCURACY)
goto output;
term*=x;
}
printf(“FINAL VALUE OF N IS NOT SUFFICIENT TO
ACHIEVE DESIRED ACCURACY”);
goto end;
output:
printf(“EXIT FROM LOOP”);
printf(“sum=%f; no. of terms=%d”, sum,n); end:
;
}
Output:
Input value of x: .21 EXIT FROM LOOP
Sum=1.265800;
No. of terms=7 Input value of x: .75
EXIT FROM LOOP
Sum=3.999774; No. of terms=34 Input value of
x:.99
FINAL VALUE OF N IS NOT
SUFFICIENT TO ACHIEVE DESIRED ACCURACY
7. Program illustrates the use of continue
statement. #include<stdio.h>
#include<conio.h>
#include<math.h>
void main()
{
int count, negative;
double number, sqroot;
printf(“enter 9999 to STOP”);
count=0;
negative=0; while(count<=100)
{
printf(“enter a number:”); scanf(“%lf”,
&number); if(number==9999)
break; if(number<0)
{
printf(“Number is negative ”); negative++;
continue;
}
sqroot=sqrt(number);
printf(“Number=%lf square root=%lf ”, number,
sqroot); count++;
}
printf(“Number of items done =%d”, count);
printf(“Negative items=%d”, negative);
printf(“END OF DATA”);
}
Output:
Enter 9999 to STOP
Enter a number: 25.0
Number=25.000000
Square root =5.000000
Enter a number: 40.5
Number =40.500000
Square root=6.363961
Enter a number:-9
Enter a number: 16
Number= 16.000000
Square root=4.000000
Enter a number: -14.75
Number is negative
Enter a number: 80
Number=80.000000
Square root=8.944272
Enter a number: 9999
Number of items done=4
Negative items=2
END OF DATA
8. Program to print binomial coefficient table. #include<stdio.h>
#include<conio.h> #define MAX 10
void
main()
{
int m, x, binom; printf(“m x”);
for (m=0; m<=10; ++m)
printf(“----------------------------------------------------------- ”);
m=0;
do
{
printf(“%2d”, m); X=0; biom=1;
while(x<=m)
{
if(m= =0 || x= =0) printf(“%4d”, binom);
else
{
binom=binom* (m-x+1)/x; printf(“%4d”, binom);
}
x=x+1;
}
printf(“\n”);
M=m+1’
}
while(m<=MAX);
printf(“-------------------------------------------------------- ”);
}
Output:
Mx
|
0
|
1
|
2
|
3
|
4
|
5
|
6
|
7
|
8
|
9
|
10
|
0
|
1
|
||||||||||
0
|
1
|
1
|
|||||||||
2
|
1
|
2
|
1
|
||||||||
3
|
1
|
3
|
3
|
1
|
|||||||
4
|
1
|
4
|
6
|
4
|
1
|
||||||
5
|
1
|
5
|
10
|
10
|
5
|
1
|
|||||
6
|
1
|
6
|
15
|
20
|
15
|
6
|
1
|
||||
7
|
1
|
7
|
21
|
35
|
35
|
21
|
7
|
1
|
|||
8
|
1
|
8
|
28
|
56
|
70
|
56
|
28
|
8
|
1
|
||
9
|
1
|
9
|
36
|
84
|
126
|
126
|
84
|
36
|
9
|
1
|
|
10
|
1
|
10
|
45
|
120
|
210
|
252
|
210
|
120
|
45
|
10
|
1
|
9. Program to draw a histogram. #include<stdio.h>
#include<conio.h>
#define N 5
void main()
{
int value[N];
int i, j, n, x;
for(n=0; n<N; ++n)
{
printf(“enter employees in group-%d: ”, n+1);
scanf(“%d”, &x);
value[n]=x;
printf(“%d”, value[n]);
}
printf(“\n”);
printf(“|\n”);
for(n=0; n<N; ++n)
{
for(i=1; i<=3; i++)
{
if(i= =2)
printf(“ Group-%d | “, n+1);
else
printf(“|”);
for(j=1;
j<=value[n]; ++j)
printf(“*”);
if(i= =2)
printf(“(%d)”, value[n]);
else
printf(“\n”);
}
printf(“|\n”);
}
}
Output:
Enter employees in Group -1:12 12
Enter employees in Group -2:23 23
Enter employees in Group -3:35 35
Enter employees in Group -4:20 20
Enter employees in Group -5:11 11
|
|************ Group-1 |************ (12)
|************
|
|*********************** Group-2 |***********************(23)
|***********************
|
|*********************************** Group-3 |***********************************(35)
|***********************************
|
|******************** Group-4 |********************(20)
|********************
|
|*********** Group-5 |***********(11)
|***********
|
10. Program of minimum
cost problem. #include<stdio.h>
#include<conio.h>
void main()
{
float p, cost, p1, cost1;
for(p=0; p<=10;
p=p+0.1)
{
cost=40-8*p+p*p;
if(p= =0)
{
cost1=cost; continue;
}
if(cost>=cost1) break; cost1=cost;
p1=p;
}
p=(p+p1)/2.0; cost=40-8&p+p*p;
printf(“MINIMUM COST=%.2f AT p=%.1f”, cost, p);
}
Output:
MINIMUM COST = 24.00 AT p=4.0
11. Program for plotting
of two functions (y1=exp(-ax); y2=exp(-ax2 /2)). #include<stdio.h>
#include<conio.h>
#include<math.h>
void main()
{
int i;
float a, x, y1, y2; a=0.4;
printf(“ Y-------> ” );
printf(“0----------------------------------------------------------------------- ”);
for(x=0; x<5; x=x+0.25)
y1=(int)
(50*exp(-a*x)+0.25);
y2=(int) (50*exp(-a*x*x/2)+0.5); if(y1= =2)
{
if(x= = 2.5)
printf(“X |”);
else printf(“|”);
for(i=1; i<=y1-1; ++i) printf(“”);
printf(“#”); continue;
}
if(y1>y2)
{
if(x= =2.5)
printf(“X |”);
else
printf(“ |”);
for(i=1; i<=y2-1; ++i) printf(“ ”);
printf(“*”);
for(i=1;
i<=(y1-y2-1); ++i)
printf(“_”);
printf(“0”); continue;
} if(x==2.5)
printf(“X|”);
else
printf(“ |”);
for(i=1; i<=y1-1; ++i) printf(“ ”);
printf(“0”);
for(i=1;
i<=(y2-y1-1); ++i)
printf(“_”);
printf(“*”);
}
}
Output:
Y--- >
0--------------------------------------------------------------------------------------------------------
| #
| 0---*
| 0---*
| 0---*
| 0---*
| 0---*
| 0---*
| 0---*
| 0---*
| 0---*
| #
12.
Write a program
using a single
–subscribed variable to evaluate the following expressions:
|
10
|
Total = 2
the values of
x1, x2,..... are read from the terminal.
i = 1
#include<stdio.h>
#include<conio.h>
void main()
{
int i;
float x[10], value, total;
printf(“ENTER 10 REAL NUMBERS”);
for(i=0; i<10; i++)
{
scanf(“%f”, &value); x[i]=value;
}
total=0.0;
for(i=0; i<10; i++)
total = total + x[i]*x[i]; printf(“\n”);
for(i=0; i<10; i++)
printf(“x[%2d] = %5.2f”, i+1, x[i]);
printf(“total=%.2f”, total);
}
Output:
ENTER 10 REAL NUMBERS
1.1 2.2 3.3 4.4 5.5 6.6 7.7 8.8 9.9 10.10
X[1]=1.10
X[2]=2.20
X[3]=3.30
X[4]=4.40
X[5]=5.50
X[6]=6.60
X[7]=7.70
X[8]=8.80
X[9]=9.90 X[10]=10.10
Total = 446.86
13. Given below is the list of marks
obtained by a class of 50 students
in an annual examination. 43 65 51 27 79 11 56 61 82 09 25 36 07 49 55 63 74 81 49 37 40 49 16 75 87 91 33 24 58 78 65 56 76 67 45 54 36 63 12 21 73 49 51 19 39 49 68 93 85 59
Write a program to count the number of students belonging
to each of the following groups of marks:
0-9,10-19,20 -29, ,100.
#include<stdio.h>
#include<conio.h>
#define MAXVAL 50
#define COUNTER 11
void main()
{
float value [MAXVAL];
int i, low, high;
int group[COUNTER]={0,0,0,0,0,0,0,0,0,0,0};
for(i=0; i<MAXVAL; i++)
{
scanf(“%f”, &value[i]);
++group[(int)(value[i]/10)];
}
printf(“\n”);
printf(“GROUP RANGE FREQUENCEY”);
for(i=0;
i<COUNTER; i++)
{
low=i*10;
if(i= =10) high=100; else
high=low+9;
printf(“%2d%3d to %3d%d”, i+1,
low, high, group[i]);
}
}
Output:
43 65 51 27 79 11 56 61 82 09 25 36 07 49 55 63 74 81 49
37 40 49 16 75 87 91 33 24 58 78
65 56 76 67 45 54 36 63 12 21 73 49 51 19 39 49 68 93 85 59 (Input data)
GROUP
|
RANGE
|
FREQUENCY
|
1
|
0 to 9
|
2
|
2
|
10 to 19
|
4
|
3
|
20 to 29
|
4
|
4
|
30 to 39
|
5
|
5
|
40 to 49
|
8
|
6
|
50 to 59
|
8
|
7
|
60 to 69
|
7
|
8
|
70 to 79
|
6
|
9
|
80 to 89
|
4
|
10
|
90 to 99
|
2
|
11
|
100 to
100
|
0
|
14. Write a program for sorting the elements of an array
in descending order.
#include<stdio.h>
#include<conio.h>
void main()
{
int *arr, temp,
i, j, n; clrscr();
printf(“enter the number of elements in the
array”); scanf(“%d”, &n);
arr=(int*)malloc(sizeof(int)*n);
for(i=0;i<n;i++)
{
for(j=i+1; j<n; j++)
{
if(arr[i]<arr[j])
{
temp=arr[i]; arr[i]=arr[j]; arr[j]=temp;
}
}
printf(“Elements of array in descending order
are”);
for(i=0; i<n; i++);
getch();
}
Output:
Enter the number of elements in the array: 5 Enter a number: 32
Enter a number: 43 Enter a number: 23
Enter a number: 57 Enter a number: 47
Elements of array in descending order are: 57
47
43
32
23
15. Write a program for finding the largest number in an array .
#include<stdio.h>
#include<conio.h>
void main()
{
int *arr, i,
j, n, LARGE; clrscr();
printf(“Enter the number of elements in the
array”); scanf(“%d”, &n);
arr=(int*)
malloc(sizeof(int)*n); for(i=0; i<n; i++)
{
printf(“Enter a number”); scanf(“%d”,
&arr[i]);
} LARGE=arr[0];
for(i=1; i<n;i++)
{
if(arr[i]>LARGE) LARGE=arr[i];
}
printf(“The largest number in the array is :
%d”, LARGE); getch();
}
Output:
Enter the number of elements in the array:5 Enter a number: 32
Enter a number: 43 Enter a number: 23 Enter a number: 57 Enter a number: 47
The
largest number in the array is : 57
16. Write a program for removing the duplicate element
in an array.
#include<stdio.h>
#include<conio.h>
#include<stdlib.h>
void main()
{
int *arr, i,
j, n, x, temp; clrscr();
printf(“Enter the number of elements in the
array”); scanf(“%d”, &n);
arr=(int*)
malloc(sizeof(int)*n); for(i=0; i<n; i++)
{
printf(“Enter a number”); scanf(“%d”,
&arr[i]);
}
for(i=0; i<n; i++)
{
for(j=i+1; j<n; j++)
{
if(arr[i]>arr[j])
{
temp=arr[i]; arr[i]=arr[j]; arr[j]=temp;
}
}
}
printf(“Elements of array after sorting”);
for(i=0; i<n; i++)
printf(“%d”,
arr[i]);
i=0;
j=1;
while(i<n)
{
if(arr[i]==arr[j])
{
for(x=j; x<n-1; x++) arr[x]=arr[x+1];
n-;
}
else
{
i++;
j++;
}
}
printf(“Elements of array after removing
duplicate elements”);
for(i=0; i<=n; i++)
printf(“%d”, arr[i]);
getch();
}
Output:
Enter the number of elements in the array:5 Enter a number: 3
Enter a number: 3 Enter a number: 4 Enter a number: 6 Enter
a number: 4
Elements of array after sorting:
3
3
4
4
6
Elements of array after removing duplicate
elements: 3
4
6
17. Write a program for finding the desired kth smallest element in an array.
#include<stdio.h>
#include<conio.h>
void main()
{
int *arr, i,
j, n, temp, k; clrscr();
printf(“enter the number of elements in the
array”); scanf(“%d”, &n);
arr=(int*)malloc(sizeof(int)*n);
for(i=0;i<n;i++)
{
printf(“Enter a number”); scanf(“%d”,
&arr[i]);
}
for(j=i+1; j<n; j++)
{
if(arr[i]<arr[j])
{
temp=arr[i]; arr[i]=arr[j]; arr[j]=temp;
}
}
}
printf(“Elements of array after sorting”);
for(i=0; i<n; i++);
printf(“%d”, arr[i]);
printf(“Which smallest element do you want to
determine”); scanf(“%d”, k);
if(k<=n)
printf(“Desired smallest element is %d”,
arr[k-1]);
else
printf(“Please enter a valid value for finding
the particular smallest element”); getch();
}
Output:
Enter the number of elements in the array:5 Enter a number: 33
Enter a number: 32 Enter a number: 46 Enter a number: 68 Enter a number: 47
Elements of array after sorting:
32
33
46
47
68
Which smallest element do you want to
determine? 3 Desired smallest element is 46
18. Program to sort a list of numbers
and to determine median. #include<stdio.h>
#include<conio.h>
#define N 10
{
int i, j, n;
float median, a[N], t;
printf(“Enter the number of items”);
scanf(“%d”, &n);
printf(“Input
%d values ”, n); for(i=1;
i<=n; i++)
scanf(“%f”, &a[i]);
for(i=1;
i<=n-1;
i++)
{
for(j=1; j<=n-1; j++)
{
if(a[j]<=a[j+1])
t=a[j]; a[j]=a[j+1]; a[j+1]=t;
}
else continue;
}
}
if(n%2 = =0)
median=(a[n/2]+a[n/2+1])/2.0;
else
median=a[n/2+1];
for(i=1; mi<=n; i++)
printf(“%f”, a[i]);
printf(“median is %f”, median);
}
Output:
Enter the number of items 5
Input 5 values
1.111 2.222 3.333 4.444 5.555
5.555000 4.444000 3.333000 2.222000 1.111000
Median is 3.333000
Enter the number of items 6
Input 6 values
3 5 8 9 4 6
9.000000 8.000000 6.000000 5.000000 4.000000 3.000000
Median is 5.500000
19. Program to calculate standard deviation. #include<stdio.h>
#include<conio.h> #include<math.h>
#define MAXSIZE 100
void main()
{
int i, n;
float value [MAXSIZE], deviation; sum=sumsqr=n=0;
printf(“Input values: input -1 to end”); for(i=1; i<MAXSIZE; i++)
{
scanf(“%f”, &value[i]); if(value[i]= =-1)
break; sum+=value[i]; n+=1;
}
mean=sum/(float)n;
for(i=1; i<=n; i++)
{
deviation=value[i]-mean;
sumsqr+=deviation* deviation;
}
variance=sumsqr/(float)n;
stddeviation=sqrt(variance);
printf(“Number of items: %d”, n); printf(“Mean:
%f”,mean);
printf(“Standard deviation:%f”,
stddeviation);
}
Output:
Input values: input -1 to end 65 9 27 78 12 20
33 49 -1
Number of items: 8 Mean: 36.625000
Standard deviation: 23.510303
20. Program to evaluate responses to a multiple-choice
test. #include<stdio.h>
#include<conio.h>
#define STUDENTS 3
#define ITEMS 25
void main()
{
char key[items+1], response[ITEMS+1];
int
count, i, student, n, correct[ITEMS+1]; printf(“Input key to the items”);
for(i=0; i<ITEMS; i++) scanf(“%c”, &key[i]);
scanf(“%c”, &key[i]); key[i]=’\0’;
for(student=1; student<=STUDENTS; student++)
{
count=0;
printf(“\n”);
printf(“Input responses of student -%d”,
student);
for(i=0; i<ITEMS; i++)
scanf(“%c”, &response[i]);
scanf(“%c”, &response[i]);
response[i]=’\0’;
for(i=0; i<ITEMS; i++) correct[i]=0;
for(i=0; i<ITEMS; i++) if(response[i]= =
key[i])
{
count=count+1; count[i]=1;
}
printf(“\n”);
printf(“student-%d”, student);
printf(“score is %d out of %d”, count, ITEMS);
printf(“Response to the items below are wrong”); n=0;
for(i=0; i<ITEMS; i++) if(correct[i]= =0)
{
printf(“%d”, i+1); n=n+1;
}
if(n= =0) printf(“NIL”);
printf(“\n”);
}
}
Output:
Input key to the items
abcdabcdabcdabcdabcdabcda
Input responses of student-1
abcdabcdabcdabcdabcdabcda
student-1
score is 25 out of 25
response to the following items are wrong NIL
Input responses of student-2
abcddcbaabcdabcdddddddddd
student-2
score is 14 out of 25
Response to the following items are wrong 5
6 7 8 17 18 19 21 22 23 25
Input responses of student-3 aaaaaaaaaaaaaaaaaaaaaaaa
student-3
score is 7 out of 25
Response to the following items are wrong
2 3 4 6 b7 8 10 11 12 14 15 16 18 19 20 22 23 24
21. Program for production and sales analysis. #include<stdio.h>
#include<conio.h>
void main()
{
int M[5][6], s[5][6], c[6], Mvalue[5][6],
Svalue [5][6],Mweek[5], Sweek[5], Mproduct[6], Sproduct[6], Mtotal, Stotal, i,
j, number;
printf(“Enter products
manufactured week wise”);
for(i=1; i<=4; i++)
for(j=1; j<=5; j++)
scanf(“%d”, &M[i][j]);
printf(“Enter products sold week wise”);
printf(“S11, S12,-, S21,S22,- etc”);
for(i=1; i<=4; i++)
for(j=1; j<=5; j++)
scanf(“%d”, &S[i][j]);
printf(“enter the cost of each product”);
for(j=1;j<=5; j++)
scanf(“%d”, &C[j]);
for(i=1; i<=4; i++)
for(j=1; j<=5; j++)
{
Mvalue[i][j]=M[i][j]*c[j];
Svalue[i][j]=S[i][j]*c[j];
}
for(i=1; i<=4; i++)
{
Mweek[i]=0; Sweek[i]=0;
for(j=1; j<5; j++)
{
Mweek[i] +=Mvalue[i][j];
Sweek[i]+= Svalue[i][j];
}
}
for(j=1; j<=5; j++)
{
Mproduct[j]=0; Sproduct[j]=0;
for(i=1; i<=4; i++)
{
Mproduct[i] +=Mvalue[i][j];
Sproduct[i]+= Svalue[i][j];
}
Mtotal=stotal=0; for(i=1; i<=4; i++)
{
Mtotal+=Mweek[i];
Stotal+=Sweek[i];
}
printf(“\n\n”);
printf(“Following is the list of things you can ”);
printf(“request for enter appropriate item
number and press RETURN key”); printf(“1. Value matrices of production &
sales”);
printf(“2. Total value of weekly production
& sales”); printf(“3. Product-wise monthly value of production&
sales”); printf(“4. Grand total value of production & sales”);
printf(“5.Exit”);
number=0; while(1)
{
printf(“ENTER YOUR CHOICE:”);
scanf(“%d”, &number); printf(“\n”);
if(number= =5)
{
printf(“GOOD BYE”); break;
}
switch(number)
{
case 1:
printf(“VALUE MATRIX OF PRODUCTION”);
for(i=1; i<=4; i++)
{
printf(“Week (%d), i”);
for(j=1; j<=5; j++)
printf(“%7d”, Mvalue);
printf(“\n”);
}
printf(“VALUE MATRIX OF SALES”);
for(i=1; i<=4; i++)
{
printf(“Week(%d)”, i);
for(j=1; j<=5; j++)
printf(“%7d”, Svalue[i][j]); printf(“\n”);
}
break; case 2:
printf(“TOTAL WEEKLY PRODUCTION & SALES”); printf(“ PRODUCTION SALES”);
printf(“ -------------- ---- ”);
for(i=1; i<=4; i++)
{
printf(“week(%d”, i);
printf(“%7d%7d”, Mweek[i], Sweek[i]);
}
break; case 3:
printf(“PRODUCT WISE TOTAL
PRODUCTION & SALES”); printf(“ PRODUCTION SALES”);
printf(“
|
--------------
|
----
|
”);
|
for(j=1; j<=5; j++)
|
|||
{
|
|||
printf(“Product(%d”,ji);
|
printf(“%7d%7d”, Mproduct[j], Sproduct[j]);
}
break; case 4:
printf(“GRAND TOTAL OF PRODUCTION SALES”);
printf(“Total production=%d”, Mtotal); break;
default:
printf(“Wrong choice, select gain”); break;
}
}
Printf(“Exit from the program”);
}
Output:
Enter products manufactured week wise M11, M12, ----, M21, M22, etc
11
|
15
|
12
|
14
|
13
|
13
|
13
|
14
|
15
|
12
|
12
|
16
|
10
|
15
|
14
|
14
|
11
|
15
|
13
|
12
|
Enter products sold week wise S11, S12,
----, S21, S22,------------------------------ etc
10 13 9 12 11
12 10 12 14 10
11 14 10 14 12
12 10 13 11 10
Enter cost of each product 10 20 30 15 25
Following is the list of things you can
request for enter appropriate item number and press RETURN key.
1.
Value matrices
of production & sales
2. Total value of weekly production & sales
3. Product-wise monthly value of production & sales
4. Grand total value of production & sales
5. Exit
Enter your choice: 1
VALUE MATRIX OF PRODUCTION
Week (1)
|
110
|
300
|
360
|
210
|
325
|
Week (2)
|
130
|
260
|
420
|
225
|
300
|
Week (3)
|
120
|
320
|
300
|
225
|
350
|
Week (4)
|
140
|
220
|
450
|
210
|
300
|
VALUE MATRIX OF SALES
Week (1)
|
100
|
260
|
270
|
180
|
275
|
Week (2)
|
120
|
200
|
360
|
210
|
250
|
Week (3)
|
110
|
280
|
300
|
210
|
300
|
Week (4)
|
120
|
200
|
390
|
165
|
250
|
Enter your choice: 2
TOTAL WEEKLY
PRODUCTION & SALES PRODUCTION SALES
Week(1)
|
1305
|
1085
|
|
Week(2)
|
1335
|
1140
|
|
Week(3)
|
1305
|
1200
|
|
Week(4)
|
1315
|
1125
|
Enter your choice: 3
PRODUCT WISE TOTAL PRODUCTION & SALES PRODUCTION SALES
Product(1)
|
500
|
450
|
|
Product(2)
|
1100
|
450
|
|
Product(3)
|
1530
|
450
|
|
Product(4)
|
855
|
450
|
|
Product(5)
|
1275
|
1075
|
Enter your choice: 4
GRAND TOTAL OF PRODUCTION SALES
Total production=5260
Total sales=4550
ENTER YOUR CHOICE:5 GOOD BYE
Exit from the program
22. Write a program to read a series of words from a
terminal using scanf function.
#include<stdio.h>
#include<conio.h>
void main()
{
char word1[40], word2[40], word3[40],
word4[40]; printf(“enter text:”);
scanf(“%s%s”, word1, word2);
scanf(“%s”, word3);
scanf(“%s”, word4);
printf(“\n”);
printf(“word1=%s\nword2=%s\n”, word1, word2);
printf(“word3=%s\nword4=%s\n”, word3, word4”);
}
Output:
Enter text:
Seventh Street, sakthinagar, erode
Word1=seventh Word2=street Word3=sakthinagar
Word4=erode
23.
Program
to read a line of text from terminal.
#include<stdio.h>
#include<conio.h> void main()
{
char line[81], character;
c=0;
printf(“Enter text. Press<return> at
end”);
do
{
charcter=getchar(); line[c]=character;
c++;
}
while(character!=’\n’);
c=c-1;
line[c]=’\0’;
printf(“\n%s\n”, line);
}
Output:
Enter text.press<return> at end Programming in c is interesting
Programming in c is interesting Enter text. Press <Return> at end
24. Write a program to copy one string into another and count the number of characters copied.
#include<stdio.h>
#include<conio.h>
void main()
{
char string1[80], string2[80];
int i;
printf(“Enter a string\n”); printf(“?”);
scanf(“%s, string2”);
for(i=0; string2[i]!=’\0’; i++) string1[i]=string2[i];
string1[i]=’\0’;
printf(“\n”);
printf(“%s\n”, string1);
printf(“number of charcters = %d\n”, i);
}
Output:
Enter a string
? Manchester Manchester
Number of characters=10
Enter a string
?westminister
Westiminister
Number of characters=11
25. Program for printing of the alphabet set in
decimal and character form.
#include<stdio.h>
#include<conio.h>
void main()
{
char c; printf(“\n\n”);
for(c=65; c<=122; c=c+1)
{
if(c>90&&c<97) continue;
printf(“|%4d-%c”, c,c);
}
printf(“|n”);
}
Output:
|65-A|66-B|67-C|68-D|69-E|70-F
|71-G|72-H|73-I|74-J|75-K|76-L
|77-M|78-N|79-O|80-P|81-Q|82-R
|83-S|84-T|85-U|86-V|87-W|88-X
|89-Y|90-Z|97-A|98-B|99-C|100-d
|101-e|102-f|103-g|104-h|105-i|106-j
|107-k|108-l|109-m|110-n|111-o|112-p
|113-q|114-r|115-s|116-t|117-u|118-v
|119-w|120-x|121-y|122-z|
26. Program to concatenation of strings. #include<stdio.h>
#include<conio.h>
void main()
{
int i, j, k;
char first_name[10]={ANANDA};
char second_name[10]={MURUGAN};
char
last_name[10] = {SELVARAJ};
char name[30];
for(i=0; first _name[i]!=‘\0’; i++) name[i]=first_name[i]; name[i]=’ ’;
for(j=0; second _name[j]!=‘\0’;j++) name[i+j+1]=second_name[j];
name[i+j+1]=’ ’;
for(k=0; last
_name[k]!=‘\0’;k++) name[i+j+k+2]=‘\0’;
printf(“\n\n”);
printf(“%s\n”, name);
}
Output:
ANANDA MURUGAN SELVARAJ
27. Program to illustration of string handling
functions. #include<stdio.h>
#include<conio.h>
#include<string.h>
void main()
{
char s1[20], s2[20], s3[20];
int x, l1,l2,l3;
printf(“enter two string constants”);
printf(“?”);
scanf(“%s %s”, s1,s2); x=strcmp(s1,s2); if(x!=0)
{
printf(“strings are not equal”); strcat(s1, s2);
}
else
printf(“strings are equal”); strcpy(s3,s1); l1=strlen(s1);
l2=strlen(s2); l3=strlen(s3);
printf(“s1=%s length =%d
characters”, s1,l1); printf(“s2=%s
length =%d characters”, s2,l2);
printf(“s3=%s length =%d characters”, s3,l3);
}
Output:
Enter two string constants
? ananda murugan
Strings are not equal
S1=ananda murugan length=13 characters
S2=murugan length=7 characters S3=ananda murugan length=13 characters
Enter two string constants
? anand anand Strings are equal
S1=anand length=5 characters
S2=anand length=5 characters S3=anand length=5 characters
28. Write a program that would sort a list of names in alphabetical order.
#include<stdio.h>
#include<conio.h> #define ITEMS 5
#define MAXCHAR 20
void main()
{
char string[ITEMS][MAXCHAR], dummy[MAXCHAR];
int i=0, j=0;
printf(“enter names of %d items”, ITEMS);
while(i<ITEMS)
scanf(“%s”, string[i++]);
for(i=1;
i<ITEMS; i++)
{
for(j=1; j<=ITEMS-i; j++)
{
if(strcmp(string[j-1), string[j]>0)
{
strcpy(dummy,
string[j-1]);
strcpy(string[j-1], string[j]);
strcpy(string[j], dummy);
}
}
}
printf(“alphabetical list”); for(i=0;
i<ITEMS; i++) printf(“%s”, string[i]);
}
Output:
enter names of 5 times
Ananda
murugan renuka devi shri
alphabetical list
Ananda devi murugan renuka shri
29. Programs for counting of characters, words and
lines in a text. #include<stdio.h>
#include<conio.h>
void main()
{
char line[81], ctr;
int i, c, end=0, characters =0, words=0.
lines=0; printf(“KEY IN THE TEXT”);
printf(“GIVE ONE SPACE AFTER EACH WORD WHEN
COMPLETED, PRESS RETURN”);
while(end= =0)
{
c=0;
while((ctr=getchar()) !=’\n’) line[c++]=ctr;
line[c]=’\0’;
if(line[0] = =’\0’) break;
else
{
words++;
for(i=0; line[i]!=’\0’; i++)
if(line[i] = =’ ‘ || line[i] = = ‘\t’)
words++;
}
lines=lines+1;
characters =characters + strlen(line);
}
printf(“\n”);
printf(“number of lines=%d”, lines);
printf(“number of words=%d”, words); printf(“number of characters=%d”,
characters);
}
Output:
KEY IN THE TEXT
GIVE ONE SPACE AFTER EACH WORD WHEN COMPLETED, PRESS
RETURN
Admiration is a very short-lived passion. Admiration involves a glorious obliquity of vision.
Always we like those who admire us but we do
not like those whom we admire. Fools admire, but men of sense approve
Number of lines=4 Number of words=36 Number of characters=205
30. Program to alphabetize a customer list. #include<stdio.h>
#include<conio.h>
#define CUSTOMERS 10
void main()
{
char first_name[20] [10], second_name[20][10],
surname[20][10], name[20][20], telephone[20][10], dummy[20];
int i,j;
printf(“input names and telephone numbers”);
printf(“?”);
for(i=0; i<CUSTOMERS; i++)
{
scanf(“%s %s %s %s”, first_name[i],
second_name[i], surname[i], telephone[i]); strcpy(name[i], surname[i]);
strcat(name[i], “ ,”);
dummy[0]=first_name[i][0]; dummy[1]=’\0’; strcat(name[i], dummy); strcat(name[i],
“.”);
dummy[0]=second_name[i][0]; dummy[1]=’\0’;
strcat(name[i], dummy);
}
for(i=1; i<=CUSTOMERS-1; i++) for(j=1;
j<=CUSTOMERS-i; j++)
if(strcmp(name[j-1], name[j])>0)
{
strcpy(dummy,
name[j-1]); strcpy(name[j-1], name[j]); strcpy(name[j], dummy);
strcpy (dummy, telephone[j-1]);
strcpy(telephone[j-1], telephone[j]); strcpy(telephone[j], dummy);
}
printf(“CUSTOMERS LIST IN ALPHABETICAL ORDER”);
for(i=0; i<CUSTOMERS; i++)
printf(“%-20s\t%-10s”, name[i], telephone[i]);
}
Output:
Input names and telephone numbers
? anandamurugan 9486153102
Renukadevi 9486644542
CUSTOMERS LIST IN ALPHABETICAL ORDER
anandamurugan 9486153102
Renukadevi 9486644542
31. Program for functions
with no arguments and no return values
#include<stdio.h>
#include<conio.h>
void printline(void);
void value (void);
void main()
{
printline();
value(); printline();
}
void printline(void)
{
int i;
for(i=1; i<=35; i++) printf(“%c”, ‘-‘);
printf(“\n”);
}
void value(void)
{
int year, period;
float inrate, sum, principal;
printf(“principal amount?”); scanf(“%f”, &principal); printf(“interest
rate?”); scanf(“%f”, &inrate); printf(“period?”);
scanf(“%d”, &period);
sum=principal;
year=1;
while(year<=period)
{
sum=sum*(1+inrate); year=year+1;
}
printf(“\n%8.2f %5.2f %5d %12.2f\n”, principal, inrate,
period, sum);
}
 |
Output:
Principal amount? 5000
Interest rate? Period?
|
0.12
|
5
|
|
5000.00
|
0.12
|
5
|
8811.71
|
 |
32. Program for functions
with arguments but no return values.
#include<stdio.h>
#include<conio.h>
void printline(char
c);
void value (float,
float, int);
void main()
{
float principal, inrate; int period;
printf(“Enter principal amount, interest”);
printf(“rate and period”);
scanf(“%f %f %d”, & principal,
&inrate, &period); printline(‘c’);
}
void printline(char ch)
{
int i;
for(i=1; i<=52; i++) printf(“%c”, ch);
printf(“\n”);
}
void value(float p, float r, int n)
{
int year; float sum; sum=p; year=1;
while(year<=n)
{
sum=sum*(1+r); year=year+1;
}
printf(“%f\t%f\t%d\t%f\n”, p, r,n,sum);
}
Output:
Enter principal amount, interest rate, and
period 5000 0.12 5
ZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZ 5000.000000 0.120000 5 8811.708984
cccccccccccccccccccccccccccccccccccccccccccccccccccccc
33. Program for functions with arguments and
return values. #include<stdio.h>
#include<conio.h>
void printline(char ch, int len);
value (float, float, int);
void main()
{
float principal, inrate,
amount;
int period;
printf(“enter principal amount, interest”);
printf(“rate, and period”);
scanf(“%f%f%d”, &principal, &inrate,
&period); printline(‘*’, 52);
amount=value(principal,
inrate, period); printf(“\n%f\t%f\t%f\t%d\t%f\n\n”, principal, inrate, period, amount); printline();
}
void printline(char ch, int len)
{
int i;
for(i=1; i<=len; i++) printf(“%c”,ch);
printf(“\n”);
}
value(float p, float r, int n)
{
int year; float sum; sum=p; year=1;
while(year<=n)
{
Sum=sum*(1+r);
year=year+1;
}
return(sum);
}
Output:
Enter principal amount,
interest rate, and period 5000
0.12 5
****************************************************************************
5000.000000 0.1200000 5 8811.00000
= = = = = = = = = = = = = = = =
= = = = = = = = = = = = = = = = = = = = = = = = = = = = = =
= = = =
34.
Write a
function power that computes x raised to the power y for integers x and y and
returns double-type value.
#include<stdio.h>
#include<conio.h>
void main()
{
int x,y;
double power (int, int); printf(“enter x,y:
”);
scanf(“%d%d”, &x,&y);
printf(“%d to power %d is %f”, x,y, power (x,y));
}
double power (int x, int y);
{
P=1.0;
if(y>=0)
while(y--) p*=x; else
while(y++) p/=x; return(p);
}
Output:
Enter x,y: 16 2
16 to power 2 is 256.000000
Enter x,y : 16 -2
16 to power -2 is 0.003906
35. Write a program to show how user-defined function
is called. #include<stdio.h>
#include<conio.h>
void main()
{
int x=1, y=2, z;
z=add(x,y);
printf(“z=%d”,
z);
}
add(a,b);
{
return(a+b);
}
Output:
z=3
36. Write a program to define user-defined function.
Call them at different places.
#include<stdio.h>
#include<conio.h>
void y();
voidy()
{
printf(“Y”); void main()
{
clrscr();
y();
a();
b();
c();
d();
}
void a()
{
printf(“A”); y();
}
void b()
{
printf(“B”); a();
}
void c()
{
a();
b();
printf(“C”);
}
void d()
{
printf(“D”); c();
b();
a();
}
Output:
YAYBAYAYBAYCDAYBAYCBAYAY
37. Write a program to show how similar variable names
can be used in different functions.
#include<stdio.h>
#include<conio.h>
void main()
{
int b=10, c=5; return();
printf(“In main() B=%d C=%d”, b,c);
fun();
}
fun()
{
int b=20, c=10;
printf(“In fun() B=%d c=%d”, b,c);
}
Output:
In main() B=10 c=5 In fun() B=20 c=10
38. Write a program to show the effect of global variables on different
functions.
#include<stdio.h>
#include<conio.h> int b=10, c=5;
void main()
{
clrscr();
printf(“In main () B=%d c=%d”, b,c);
fun();
b++; c--;
printf(“Again In main () B=%d
c=%d”, b,c);
}
fun()
{
b++; c--;
printf(“ In fun () B=%d c=%d”, b,c);
}
Output:
In main() B=10 c=5 In fun() B=11 c=4
Again In main() B=12 c=3
39. Write a program to display message
using user-defined function. #include<stdio.h>
#include<conio.h>
void main()
{
void message();
message();
}
void message()
{
puts (“Have a nice day”);
}
Output:
Have a nice day
40. Write a program to return more than one value from user defined
function.
#include<stdio.h>
#include<conio.h>
void main()
{
int x,y, add, sub, change(int*, int*,
int*, int*); clrscr();
printf(“Enter values of X and Y:”); scanf(“%d
%d”, &x, &y);
change(&x &y, &add, &sub);
printf(“Addition:%d”, add); printf(“Subtraction:%d”, sub);
return 0;
}
change(int * a, int*b, int*c, int d)
{
c=*a+*b;
*d=*a-*b;
}
Output:
Enter values of x & y: 5 4 Addition: 9
Subtraction:1
41. Write a program to pass arguments to user-defined function by value and by reference.
#include<stdio.h>
#include<conio.h>
void main()
{
int k, m, other(int, int*); clrscr();
printf(“Address of k&m in main(): %u%u”,
&k&m); other(k&m);
return 0;
}
other(int k, int*m)
{
printf(“Address of k&m in other(): %u%u, &k,m”);
}
Output:
Address of k&m in main(): 65524 65522
Address of k&m in other(): 65518 65522
42. Write a program to return only absolute value like abs() function.
#include<stdio.h>
#include<conio.h>
void main()
{
int uabs(int), x; clrscr();
printf(“enter a negative value:”);
scanf(“%d”,
x);
x=uabs(x);
printf(“X=%d”, x); return 0;
}
uabs(int y)
{
if(y<0) return(y*-1); else return(y);
}
Output:
Enter a negative value: -5 X=5
43.
Write a
program to calculate square and cube of an entered number. Use function as an argument.
#include<stdio.h>
#include<conio.h>
void main()
{
int m; clrscr();
printf(“Cube: %d”,
cube(sqr(input())));
}
input()
{
int k; printf(“Number:”);
scanf(“%d”, &k); return k;
}
sqr(m)
{
printf(“Square:%d”, m*m);
return m;
}
cube(m)
{
return m*m*m;
}
Output:
Number:2 Square: 4 Cube:8
44. Write a program to assign return
value of a function to another variable.
#include<stdio.h>
#include<conio.h>
void main()
{
int input(int); int x; clrscr(); x=input(x);
printf(“x=%d”, x);
}
input(int k)
{
printf(“Enter value of x=”); scanf(“%d”, &k);
return(k);
}
Output:
Enter value of x=5 x=5
45. Write a program
to perform addition
and subtraction of numbers with return value of function.
#include<stdio.h>
#include<conio.h>
#include<math.h>
void main()
{
int input(int);
int sqr(int);
int x;
clrscr();
x=sqr(1-input(x)+1); printf(“Square=%d, x”);
}
input(int k)
{
printf(“Enter value of x=”); scanf(“%d, &k”); return(k);
{
sqr(int m)
{
return (pow(m,2));
}
Output:
Enter value of x=5 Square=9
46. Write a
program to perform multiplication and division of numbers with return value of function.
#include<stdio.h>
#include<conio.h> #include<math.h>
void main()
{
int input(int);
int sqr(int); int x; clrscr();
x=sqr(5*input(x)/2); printf(“Square=%d, x”);
}
input(int k)
{
printf(“Enter value of x=”); scanf(“%d, &k”); return(k);
{
sqr(int m)
{
return (pow(m,2));
}
Output:
Enter value of x=5 Square=144
47. Write a program to use (++) operator with return
value of function.
#include<stdio.h>
#include<conio.h>
#include<math.h>
void main()
{
int input(int);
int sqr(int);
irit x,y =0;
clrscr();
x=sqr(++(y-(input(x))));
printf(“Square=%d”,
x);
}
input(int k)
{
printf(“Enter value of x=”); scanf(“%d”, &k); return(k);
}
sqr(int m)
{
return (pow(m,2));
}
Output:
Enter value of x=7 Square=64
48. Write a program to use mod(%) with function. #include<stdio.h>
#include<conio.h>
void main()
{
int j();
if(j()%2= =0)
printf(“Number is odd”);
return 0;
}
j()
{
int x; clrscr();
printf(“Enter a number”); scanf(“%d”, &x);
return(x);
}
Output:
Enter a number:5 Number is odd
49. Write a program to evaluate the equation s=sqr(a()+b()) using function.
#include<stdio.h>
#include<conio.h>
void main()
{
int s=0, a(),
b(),sqr(int); clrscr();
s=sqr(a()+b());
printf(“square of sum=%d”, s);
return 0;
}
a()
{
int a;
printf(“Enter value of a:”); scanf(“%d”,
&a); return(a);
}
b()
{
int b;
printf(“Enter value of b:”); scanf(“%d”,
&b); return(b);
}
sqr(int x)
{
return(x*x);
}
Output:
Enter value of a:5 Enter value of b: 3 Square of sum=64
50. Write a program to call user-defined function through if statement.
#include<stdio.h>
#include<conio.h>
void main()
{
int a();
clrscr();
if(a()%2= =0)
printf(“The number is even”);
else
printf(“The number is odd”);
}
a()
{
int a;
printf(“Enter value of a:”);
scanf(“%d”,&a); return(a);
}
Output:
Enter value of a:5 The number is odd
51. Write a program to call user-defined function through switch()
statement.
#include<stdio.h>
#include<conio.h>
#include<math.h>
#include<ctype.h>
void main()
{
int a();
int x=5;
clrscr();
switch(a())
{
case’s’:
printf(“Square of %d is %d”, x, pow(x,2));
break;
case’c’:
printf(“Cube of %d is %d”, x, pow(x,3));
break;
case’d’:
printf(“Double of %d is %d”, x, x*2); break;
default:
printf(“Unexpected choice printed as it is : %d”, x);
}
}
a()
{
char c=’c’;
printf(“Enter your choice square(s), cube(c),
double(d):”); c=getche();
c=tolower(c); return(c);
}
Output:
Enter your choice square(s), cube(c), double
(d):D Double of 5 is 10
52. Write a program to call function
through the for loop.
#include<stdio.h>
#include<conio.h>
#include<process.h>
void main()
{
int plus(int), m=1; clrscr();
for(; plus(m); m++)
{
printf(“%3d”, m);
}
}
plus (int k)
{
if(k= =10)
{
exit(1);
return NULL;
}
else return(k);
}
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